Question

if x-1/x =3+2√2 find the value of x²+1/x²
please tell the answer no spaaming​

Answer 1

Answer:

${x}^{2} + \frac{1}{ {x}^{2} } = 19 + 12 \sqrt{2}$

Step-by-step explanation:

$x - \frac{1}{x} = 3+ 2 \sqrt{2} \\ squaring \: on \: both \: the \: sides \\ {(x - \frac{1}{x}) }^{2} = {(3 + 2 \sqrt{2} )}^{2} \\ {(x)}^{2} + { (\frac{1}{x} )}^{2} - 2(x)( \frac{1}{x} ) = {(3)}^{2} + {(2 + \sqrt{2}) }^{2} + 2(3)(2 \sqrt{2} ) \\ {x}^{2} + \frac{1}{ {x}^{2} } - 2 = 9 + 8 + 12 \sqrt{2} \\ {x}^{2} + \frac{1}{ {x}^{2} } = 9 + 8 + 2 + 12 \sqrt{2} \\ {x}^{2} + \frac{1}{ {x}^{2} } = 19 + 12 \sqrt{2}$

Answer 2

are taarif kari yaar

hain hi itte pyare woh XD