if x-1/x= 3 +2 square root 2 ... find the value of 1/4 (x^3-1/x^3)
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x - 1/x = 3 +2√2
x³ -1/x³ =(x -1/x)³ +3(x -1/x)
=(3+2√2)³ +3(3+2√2)
=(3+2√2){17+12√2 + 3}
=( 3+2√2){20+12√2)
=4(3+2√2)(5+3√2)
=4(15 +9√2 +10√2+12)
=4(27 +19√2)
now, 1/4( x³ -1/x³) =1/4{4(27+19√2}
=(27+19√2) ( answer )
x³ -1/x³ =(x -1/x)³ +3(x -1/x)
=(3+2√2)³ +3(3+2√2)
=(3+2√2){17+12√2 + 3}
=( 3+2√2){20+12√2)
=4(3+2√2)(5+3√2)
=4(15 +9√2 +10√2+12)
=4(27 +19√2)
now, 1/4( x³ -1/x³) =1/4{4(27+19√2}
=(27+19√2) ( answer )
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