Question

If (x-1) , (x+3) ,(3x-1) are Ap then find the value of x

Answer 1

hey mate here is your answer

when three terms are in ap

then

b=(a+c)/2

X+3=((x-1)+(3x-1))/2

2x+6=4x-2

2x=8

X=4

hope it will help you

mark me brainliest ✌✌✌

Answer 2

The value of x is 4

Given

(x-1), (x+3), (3x-1) are in Arithmetic progression

To Find

The value of x

Solution

We are given that the terms (x-1), (x+3), and (3x-1) are in Arithmetic progression

Let us assume the first term as 'a' second term as 'b' and the third term as 'c'

when three terms in an arithmetic progression then b= $\frac{a+c}{2}$

Therefore from the given terms (x+3) = $\frac{(x-1)+(3x-1)}{2}$

Solving the equation it becomes 2(x+3)=x-1+3x-1

which is equal to 2x + 6=4x - 2

therefore 2x = 8 and x =4

Hence the value of x is 4