if x-1,x+3,3x-1 are in A. p then x=?
Answers
Answered by
5
they are in ap so their common difference will be equal
x+3-(x-1)=3x-1-(x+3)
x+3-x+1=3x-1-x-3
4=2x-4
2x=8
x=4
x+3-(x-1)=3x-1-(x+3)
x+3-x+1=3x-1-x-3
4=2x-4
2x=8
x=4
Answered by
2
We know that an AP have common difference between adjacent terms
a2-a1=a3-a2
(x+3)-(x-1)=(3x-1)-(x+3)
x+3-x+1=3x-1-x-3
4=2x-4
2x=8
x=8/2=4
Hope that this helps you (^_^)b
a2-a1=a3-a2
(x+3)-(x-1)=(3x-1)-(x+3)
x+3-x+1=3x-1-x-3
4=2x-4
2x=8
x=8/2=4
Hope that this helps you (^_^)b
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