Math, asked by tamahar9, 1 year ago

if x+1/x=3,evaluate x^3+1/x^3​

Answers

Answered by Siddharta7
4

Given: x+1/x = 3

Cubing both sides

(x+1/x)^3 = 3^3

Now, using the formula ( a+b)^3

x^3 + 1/x^3 + 3× x × 1/x ( x+ 1/x) = 27

x^3 + 1/x^3 + 3 (x+1/x) = 27

x^3 + 1/x^3 + 3 (3) = 27

x^3 + 1/x^3 = 27-9

x^3 + 1/x^3 = 18

Answered by Souviksvk10
4

Step-by-step explanation:

x +  \frac{1}{x}  = 3

Then,

 {x}^{3}  +  \frac{1}{ {x}^{3} }  \\  = {(x +  \frac{1}{x}) }^{3}  - 3x \frac{1}{x} (x +  \frac{1}{x} ) \\  =  {3}^{3}  - 3 \times 3 \\  = 27 - 9 \\  = 18

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