Question

If (x+ 1/x) = 3 find the value of x^18 + x^12 + x^6 + 1​

Answer 1

Answer:

If (x+ 1/x) = 3

Then,

x^18 + x^12 + x^6 + 1

$= {x}^{15} ( {x}^{3} + \frac{1}{ {x}^{3} } ) + {x}^{3} ( {x}^{3} + \frac{1}{ {x}^{3} } ) \\ \\ ( {x}^{15} + {x}^{3})( {x}^{3} + \frac{1}{ {x}^{3} } )$