If x-1/x=3 find the value of x^2+1/x^2 please answer fastly
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Answer:
(1) An equation in the form ax + by + c = 0, where a, b and c are real numbers, and a≠ 0 and b ≠ 0, is called a linear equation in two variables x and y. For Example: 2x + 3y + 7 = 0, where a = 2, b = 3, c =5 are real numbers. So, given equation is a linear equation in two variables.
We know , (X+1/x)^2 = x^2 + (1/x)^2 + 2(x * 1/x)
We know , (X+1/x)^2 = x^2 + (1/x)^2 + 2(x * 1/x)=> (X+1/x)^2 = x^2 + (1/x)^2 + 2
We know , (X+1/x)^2 = x^2 + (1/x)^2 + 2(x * 1/x)=> (X+1/x)^2 = x^2 + (1/x)^2 + 2Substituting value from (i) (3)^2 = x^2+(1/x)^2+2
We know , (X+1/x)^2 = x^2 + (1/x)^2 + 2(x * 1/x)=> (X+1/x)^2 = x^2 + (1/x)^2 + 2Substituting value from (i) (3)^2 = x^2+(1/x)^2+2= 9–2 = x^2+(1/x)^2
We know , (X+1/x)^2 = x^2 + (1/x)^2 + 2(x * 1/x)=> (X+1/x)^2 = x^2 + (1/x)^2 + 2Substituting value from (i) (3)^2 = x^2+(1/x)^2+2= 9–2 = x^2+(1/x)^2Ans. X^2 + (1/x)^2 = 7.
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