Question

If x+1/x = √3 , Find the value of x^3 + 1/x^3​

Answer 1

HIII.......

Answer:

18

Step-by-step explanation:

Given: x+1/x = 3

Cubing both sides

(x+1/x)^3 = 3^3

Now, using the formula ( a+b)^3

x^3 + 1/x^3 + 3× x × 1/x ( x+ 1/x) = 27

x^3 + 1/x^3 + 3 (x+1/x) = 27

A/q: x+ 1/x = 3

x^3 + 1/x^3 + 3 (3) = 27

x^3 + 1/x^3 = 27-9

x^3 + 1/x^3 = 18

MARK ME AS BRAINLIST

HOPE IT HELPS

DO REPLY

Answer 2

$x+\frac{1}{x}=\sqrt{3}$

Cubing both sides :

$(x+\frac{1}{x})^3=(\sqrt{3})^3$

Identity : (a + b)³ = a³ + b³ + 3ab (a + b)

$(x^3+\frac{1}{x^3})+3*x*\frac{1}{x}(x+\frac{1}{x})=3\sqrt{3}\\ \\(x^3+\frac{1}{x^3})+3(x+\frac{1}{x})=3\sqrt{3}$

Given that x + 1/x = √3 :

$(x^3+\frac{1}{x^3})+3\sqrt{3}=3\sqrt{3}$

$x^3+\frac{1}{x^3}=0$