if x+1/x=3 , find the values of x²+1/x² and x^4+1/x^4
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in this kind of questions just square the RHS and subtract it by two,and that's your answer.
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ansh85:
answer is only 7
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Hey,
X+1/x=3
(x+1/x) ^2=3^2
x^2+1/x^2+2x*1/x=9
x^2+1/x^2=7,,,,,,,,,,,,,, 1)
And again
(x+1/x)^4=3^4
x^4+1/x^4+2x^2*1/x^2=81
x^4+1/x^4=79
X+1/x=3
(x+1/x) ^2=3^2
x^2+1/x^2+2x*1/x=9
x^2+1/x^2=7,,,,,,,,,,,,,, 1)
And again
(x+1/x)^4=3^4
x^4+1/x^4+2x^2*1/x^2=81
x^4+1/x^4=79
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