Math, asked by paulsaumya08, 4 days ago

if x+1/x=3 find value of x-1/x , x2-1/x2 and x2+1/x2​

Answers

Answered by divyanshidas
2

Answer:

(x-1)/x= ½

(x²-1)/x²= -3

x²+1/x²= 5

Step-by-step explanation:

(x+1)/x=3

=> x+1=3x

=> -2x=(-1)

=> x=½

(x-1)/x= (½-1)/(½)

= [(1-2)/2]/(½)

= [(½)/2]/(½)

= (¼)/(½)

= ¼×2

= ½

(x²-1)/x²= [(½)²-1]/[(½)²]

= (¼-1)/(¼)

= [(1-4)/4]/(¼)

= [-3/4]/(¼)

= (-3/4)×4

= -3

x²+1/x²= [(½)²+1]/[(½)²]

= (¼+1)/(¼)

= [(1+4)/4]/(¼)

= [5/4]/(¼)

= (5/4)×4

= 5

hope it helps!

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