if x+1/x=3 find value of x-1/x , x2-1/x2 and x2+1/x2
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Answer:
(x-1)/x= ½
(x²-1)/x²= -3
x²+1/x²= 5
Step-by-step explanation:
(x+1)/x=3
=> x+1=3x
=> -2x=(-1)
=> x=½
(x-1)/x= (½-1)/(½)
= [(1-2)/2]/(½)
= [(½)/2]/(½)
= (¼)/(½)
= ¼×2
= ½
(x²-1)/x²= [(½)²-1]/[(½)²]
= (¼-1)/(¼)
= [(1-4)/4]/(¼)
= [-3/4]/(¼)
= (-3/4)×4
= -3
x²+1/x²= [(½)²+1]/[(½)²]
= (¼+1)/(¼)
= [(1+4)/4]/(¼)
= [5/4]/(¼)
= (5/4)×4
= 5
hope it helps!
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