Math, asked by gt2730, 3 months ago

if x+1/x=3 find x^2+1/x^2

Answers

Answered by Anonymous

(x+1/x) ^2 =x^2 + 1/x^2 X1/X

=>(3) ^2 = x^2 + 1/x^2 +2

⇒ 9=x^2 + 1/x^2 +2

=> x^2 + 1/x^2 +2 = 9

=> x^2 + 1/x^2 =9-2 =7

∴ x^2 + 1/x^2 =7

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thnkyu!

Have a great day! :)

Answered by Xiaolin74

(x+1/x) ^2 =x^2 + 1/x^2 X1/X

=>(3) ^2 = x^2 + 1/x^2 +2

⇒ 9=x^2 + 1/x^2 +2

=> x^2 + 1/x^2 +2 = 9

=> x^2 + 1/x^2 =9-2 =7

∴ x^2 + 1/x^2 =7

HOPE IT HELPS! FOLLOW ME

thnkyu!

Have a great day! :)

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if x+1/x=3 find x^2+1/x^2​

Answers

(x+1/x) ^2 =x^2 + 1/x^2 *X*1/X

∴ x^2 + 1/x^2 =7

HOPE IT HELPS! FOLLOW ME

Have a great day! :)

(x+1/x) ^2 =x^2 + 1/x^2 *X*1/X

∴ x^2 + 1/x^2 =7

HOPE IT HELPS! FOLLOW ME

Have a great day! :)

if x+1/x=3 find x^2+1/x^2

(x+1/x) ^2 =x^2 + 1/x^2 X1/X

(x+1/x) ^2 =x^2 + 1/x^2 X1/X