If x-1/x =3 , find x^3 -1/x^3.
Anyone genius in maths ,who can solve this??
Answers
Answered by
2
x - 1/x = 3 ------(1)
On cubing both sides, we get
x^3 - 1/x^3 - 3(x)(1/x)(x-1/x) = 27
=> x^3 - 1/x^3 - 3 (3) = 27 [ using equation 1]
=> x^3 - 1/x^3 - 9 = 27
=> x^3 - 1/x^3 = 36
On cubing both sides, we get
x^3 - 1/x^3 - 3(x)(1/x)(x-1/x) = 27
=> x^3 - 1/x^3 - 3 (3) = 27 [ using equation 1]
=> x^3 - 1/x^3 - 9 = 27
=> x^3 - 1/x^3 = 36
Answered by
0
x - 1/x = 3 ------(1)
On cubing both sides, we get
x^3 - 1/x^3 - 3(x)(1/x)(x-1/x) = 27
=> x^3 - 1/x^3 - 3 (3) = 27 [ using equation 1]
=> x^3 - 1/x^3 - 9 = 27
=> x^3 - 1/x^3 = 36
Similar questions