If x+ 1/x= 3. Find xsquare+1/xsquare and xcube+1/xcube
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x+1/x=3,
(x+1/x)²=3²,
x²+1/x²+2=9,
then
x²+1/x²=7,
since
x+1/x=3,
then
(x+1/x)³=3³,
x³+1/x³+3(x+1/x)=27,
x³+1/x³+3×3=27,
then
x³+1/x³=27-9=18
(x+1/x)²=3²,
x²+1/x²+2=9,
then
x²+1/x²=7,
since
x+1/x=3,
then
(x+1/x)³=3³,
x³+1/x³+3(x+1/x)=27,
x³+1/x³+3×3=27,
then
x³+1/x³=27-9=18
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