Question

if x+1/x=√3 so find the Value of x^6+1​

Answer 1

Answer:

0

Step-by-step explanation:

You can use a3+b3=(a+b)3−3ab(a+b) , with a=x,b=1/x . Therefore

x3+1x3=(x+1x)3−3(x+1x)=33–√−33–√=0

which can be transformed into

x6+1x3=0

and we can conclude x6+1=0 .