Question

if (x+1/x) = 3 , then the value of (x²+1/x²) is :​

Answer 1

$\huge\underline\bold\red{AnswEr}$

x+1/x=3

squaring on both sides

(x+1/x)^2=(3)^2

(a+b)^2=a^2+b^2+2ab

x^2+1/x^2+2*x*1/x=9

x^2+1/x^2=9–2

$\boxed{x^2+1/x^2=7}$

Answer 2

Answer:

x²+1/x² = 11

Explanation:

Given

x-1/x = 3---(1)

On Squaring equation (1), we get

=> (x-1/x)² = 3²

=> x²+1/x²-2*x*(1/x) = 9

/* By algebraic identity :

(a-b)² = a²+b²-2ab */

=> x²+1/x² - 2 = 9

=> x² + 1/x² = 9 +2

=> x² + 1/x² = 11

Therefore,

x²+1/x² = 11

••••

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