Math, asked by user123428, 3 months ago

if x+1/x=3, x^2+1/x^3=4. find x^3+1/x^2

please answer in steps​

Answers

Answered by zweckerg597
0

Answer:

if you should already know the answers because you're in second grade I'm in 6th grade and I'm better than you at math.No Offence

Step-by-step explanation:

if you should already know the answers because you're in second grade I'm in 6th grade and I'm better than you at math.No Offence

Answered by rohantarafdar
1

Answer:

2( \sqrt{5}+3)

Step-by-step explanation:

     x+1/x=3

or, (x^2+1)/x = 3

or, x^2+1 = 3x

or, x^2-3x+1 = 0

or, x^2-2.x.(3/2)+( 3/2)^2+1 = (3/2)^2

or, (x-1.5)^2+1 = 9/4

or, (x-1.5)^2 = (9/4)-1

or, (x-1.5)^2 = 5/4

or, (x-1.5) = \sqrt{5}/2

or,  x = ( \sqrt{5}/2)+(3/2)

so x = ( \sqrt{5}+3)/2

given figure =  x^3+1/x^2

                    = x( x^2+1/x^3)

                    =  {( \sqrt{5}+3)/2} x 4

                    = 2( \sqrt{5}+3)

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