Question

if x+1/x=4, find the value of x²+1/x².​

Answer 1

Answer:

Step-by-step explanation:

x+1/x = 4

Squaring on both sides:

(x+1/x)^2 = 4^2

[(a+b)^2 = a^2 + b^2 + 2ab]

x^2 + 1/x^2 + 2.x.1/x = 16

x^2 + 1/x^2 + 2 = 16

x^2 + 1/x^2 = 14

Hence Found

Hope it helped...

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Answer 2

$x + \frac{1}{x} = 4 \\ squaring \\ ({x + \frac{1}{x} })^{2} = {4}^{2} \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2( \cancel{x})( \frac{1}{ \cancel{x}} ) = 16 \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2 = 16 \\ \fbox{{x}^{2} + \frac{1}{ {x}^{2} } = 14}$

☺William☺