If (x+1/x)=4, find the value of (x²+1/x²)
Answers
Answered by
1
Answer:
x
2
+
x
2
1
=14
Step-by-step explanation:
We have,
x+\dfrac{1}{x}=4x+
x
1
=4 .....(1)
To find, x^2+\dfrac{1}{x^2}=?x
2
+
x
2
1
=?
Squaring (1) in both sides, we get
(x+\dfrac{1}{x})^{2}=4^{2}(x+
x
1
)
2
=4
2
⇒ x^2+\dfrac{1}{x^2}+2.x.\dfrac{1}{x} =16x
2
+
x
2
1
+2.x.
x
1
=16
⇒ x^2+\dfrac{1}{x^2}+2 =16x
2
+
x
2
1
+2=16
⇒x^2+\dfrac{1}{x^2}=16-2=14x
2
+
x
2
1
=16−2=14
∴ x^2+\dfrac{1}{x^2}=14x
2
+
x
2
1
=14
Hence, x^2+\dfrac{1}{x^2}=14x
2
+
x
2
1
=14
Answered by
0
Answer:
so long the answer is ok
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