If x + 1/x = 5 and x - 1/x = 3, then x^2 - 1/x^2 = ?
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Given:
x + 1/x = 5 -- equation (1)
x - 1/x = 3 -- equation (2).
On Multiplying equation (1) & (2) we get,
→ (x + 1/x) * (x - 1/x) = 5 * 3
We know that,
a² - b² = (a + b)(a - b)
Let,
- a = x
- b = 1/x
Hence,
(x)² - (1/x)² = 15
→ x² - 1/x² = 15
(or)
Adding equations (1) & (2) we get,
x + 1/x + x - 1/x = 5 + 3
→ 2x = 8
→ x = 8/2
→ x = 4
Putting the value of x in equation (1) we get,
→ 4 + 1/x = 5
→ 1/x = 5 - 4
→ 1/x = 1
Hence,
→ x² - 1/x² = (4)² - (1)²
→ x² - 1/x² = 16 - 1
→ x² - 1/x² = 15
Hence, the value of x² - 1/x² is 15.
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