Question

if x-1/x=5 find (4x^2 -4)/x^2+5x-1​

Answer 1

-4-4/ -2-5+1

. hope it helps you

Answer 2

Solution.

Note that the value of $x$ satisfies $x^2-5x-1=0$.

We found that $\boxed{x^2=5x+1}$.

$\dfrac{4x^2-4}{x^2+5x-1}$

$=\dfrac{4(5x+1)-4}{5x+1+5x-1}$

$=\dfrac{20x+4-4}{10x}$

$= \dfrac{20x}{10x} =\boxed{2}$

Required answer.

Hence, the required answer is $\dfrac{4x^2-4}{x^2+5x-1}=2$.