Question

if ( x-1/x )=5, find the value of (i) x2+1/x2) and (ii) (x4+1/x4)

Answer 1

( x - 1/x ) = 5



Square on both sides,


( x - 1/x )² = 5²

=> x² + 1/x² - 2 = 25

=> x² + 1/x² = 27 [ 1 answer ]





Again square on both sides,



=> ( x² + 1/x² )² = 27²

=> x⁴ + 1/x⁴ + 2 = 729

=> x⁴ + 1/x⁴ = 727





$.$

Answer 2

Step-by-step explanation:

Now,

For first answer Steps

Squaring both sides will give

(x-1/x) ²=(5)²

x²+1/x²-2=25 Using (a-b) ²= a²-2ab+b²

x²+1/x²=27

Now for second answer

Again squaring both sides give

(x²+1/x²) ²= (27)²

x⁴+1/x⁴+2=729

x⁴+1/x⁴=727

..