if x-1/x =5 ,find the value of x^2+1/x^2
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We have used the identity,
➡ (a+b)² = a² + 2ab + b²
The value of x² + 1/ x² is
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Given,
x - 1/x = 5
making square of both sides,
(x- 1/x)² = 5²
expand using identity:- (a-b)² = a² +b² -2ab
x² + 1/x² -2*x*(1/x) = 25
x² + 1/x² -2 = 25
x² + 1/x² =25+2
x² + 1/x² = 27
x - 1/x = 5
making square of both sides,
(x- 1/x)² = 5²
expand using identity:- (a-b)² = a² +b² -2ab
x² + 1/x² -2*x*(1/x) = 25
x² + 1/x² -2 = 25
x² + 1/x² =25+2
x² + 1/x² = 27
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