If x+1/x=5 find the value of x^2+1/x^2 and x^4+1/x^4.
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x+1/x=5
Square on both sides,
(x+1/x) ²=5²
x²+1/x²+2(x*1/x) =25
x²+1/x²+2=25
x²+1/x²=25-2
x²+1/x²=23
Again, square on both sides,
(x²+1/x²)²=23²
x⁴+1/x⁴+2{x²*1/x²} =529
x⁴+1/x⁴+2=529
x⁴+1/x⁴=529-2
x⁴+1/x⁴=527
I hope this will help you
Square on both sides,
(x+1/x) ²=5²
x²+1/x²+2(x*1/x) =25
x²+1/x²+2=25
x²+1/x²=25-2
x²+1/x²=23
Again, square on both sides,
(x²+1/x²)²=23²
x⁴+1/x⁴+2{x²*1/x²} =529
x⁴+1/x⁴+2=529
x⁴+1/x⁴=529-2
x⁴+1/x⁴=527
I hope this will help you
abhi569:
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