Math, asked by ppandey3982, 6 months ago

If x+1/x=5 find the value of x^9+1/x^9

Answers

Answered by Anonymous
2

GIVEN:-

  • \rm{ x + \dfrac{1}{x} = 5}

TO FIND :-

  • \rm{ x^9 + \dfrac{1}{x^9}}

IDENTITIES USED:-

  • \rm{(a+b)^2 = a^3 + b^3 + 3\times{a}\times{b} ( a+b)}

Now,

\implies\rm{ (x +\dfrac{1}{x}) = 5 }

  • Cubing it.

\implies\rm{ (x + \dfrac{1}{x})^3 = x^3 + \dfrac{1}{x^3} + 3\times{x}\times{\dfrac{1}{x}}( x+ \dfrac{1}{x})}

\implies\rm{ (5)^3 = x^3 + \dfrac{1}{x^3} + 3\times{x}\times{\dfrac{1}{x}} (5)}

\implies\rm{ 125 - 15 =x^3 + \dfrac{1}{x^3}}

\implies\rm{ 110 = x^3 + \dfrac{1}{x^3}}

  • Now again Cubing

\implies\rm{ (x^3 + \dfrac{1}{x^3})^3 = (x^3)^3+ \dfrac{1}{(x^3)^3} + 3\times{x^3}\times{\dfrac{1}{x^3}}( x^3+ \dfrac{1}{x^3})}

\implies\rm{ (110)^3 =(x^3)^3\dfrac{1}{(x^3)^3} + 3\times{x^3}\times{\dfrac{1}{x^3}(110)}}

\implies\rm{1331000 = x^9 + \dfrac{1}{x^9} + 3\times{110}}

\implies\rm{ 1331000-1430 =x^9 + \dfrac{1}{x^9}}

\implies\rm{ 1329570 =x^9 + \dfrac{1}{x^9}}

Answered by gsiddhant041
1

Step-by-step explanation:

(x+

x

1

)=5

Cubing it.

\implies\rm{ (x + \dfrac{1}{x})^3 = x^3 + \dfrac{1}{x^3} + 3\times{x}\times{\dfrac{1}{x}}( x+ \dfrac{1}{x})}⟹(x+

x

1

)

3

=x

3

+

x

3

1

+3×x×

x

1

(x+

x

1

)

\implies\rm{ (5)^3 = x^3 + \dfrac{1}{x^3} + 3\times{x}\times{\dfrac{1}{x}} (5)}⟹(5)

3

=x

3

+

x

3

1

+3×x×

x

1

(5)

\implies\rm{ 125 - 15 =x^3 + \dfrac{1}{x^3}}⟹125−15=x

3

+

x

3

1

\implies\rm{ 110 = x^3 + \dfrac{1}{x^3}}⟹110=x

3

+

x

3

1

Now again Cubing

\implies\rm{ (x^3 + \dfrac{1}{x^3})^3 = (x^3)^3+ \dfrac{1}{(x^3)^3} + 3\times{x^3}\times{\dfrac{1}{x^3}}( x^3+ \dfrac{1}{x^3})}⟹(x

3

+

x

3

1

)

3

=(x

3

)

3

+

(x

3

)

3

1

+3×x

3

×

x

3

1

(x

3

+

x

3

1

)

\implies\rm{ (110)^3 =(x^3)^3\dfrac{1}{(x^3)^3} + 3\times{x^3}\times{\dfrac{1}{x^3}(110)}}⟹(110)

3

=(x

3

)

3

(x

3

)

3

1

+3×x

3

×

x

3

1

(110)

\implies\rm{1331000 = x^9 + \dfrac{1}{x^9} + 3\times{110}}⟹1331000=x

9

+

x

9

1

+3×110

\implies\rm{ 1331000-1430 =x^9 + \dfrac{1}{x^9}}⟹1331000−1430=x

9

+

x

9

1

\implies\rm{ 1329570 =x^9 + \dfrac{1}{x^9}}⟹1329570=x

9

+

x

9

1

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