If x+1/x=5 find the value of x square +1/xsquare
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Answered by
3
Answer:
Step-by-step explanation:
x2−(1x)2=(x+1x)(x−1x)
We know that (a+b)2=(a−b)2+4ab
Hence, (x+1x)2=(x−1x)2+4⋅x⋅1x=25+4=29
Hence the required solution is ±529−−√
kusharora545:
Wrong answer
Answered by
22
x + 1/x = 5
or, (x+1/x)² = (5)²
or, x²+1/x²+2.x.1/x = 25
or, x² + 1/x² + 2 = 25
or, x² +1/x² = 25-2
so, x²+1/x² = 23
or, (x+1/x)² = (5)²
or, x²+1/x²+2.x.1/x = 25
or, x² + 1/x² + 2 = 25
or, x² +1/x² = 25-2
so, x²+1/x² = 23
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