if X+1/x=√5, find the value of (x²+1/x²)
full and clear explanation please
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The value of x^2 + (1/x^2) is 3.
Step-by-step explanation:
Given:
x + (1/x) = √5
To find:
the value of x^2 + (1/x^2) = ?
Solution:
We have,
x + (1/x) = √5
Squaring on both sides, we get
=> [x + (1/x)]^2 = (√5)^2
since, (a + b)^2 = a^2 + 2ab + b^2
Where, a = x and b = 1/x,
Now, we get
=> [(x)^2 + 2(x)(1/x) + (1/x)^2 = (√5)^2
=> [(x)^2 + 2 + (1/x)^2 = 5
=> [x^2 + 2 + (1/x^2) = 5
=> x^2 + (1/x^2) = 5 - 2
=> x^2 + (1/x^2) = 3
Answer:
Hence, the value of x^2 + (1/x^2) is 3.
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