If x-1/x= 5, find x^2+1/x^2
Answers
Answered by
0
Answer:
12 is the answer
Step-by-step explanation:
a−
a
1
=5
Squaring both sides,
=>(a−
a
1
)
2
=5
2
=>a
2
+
a
2
1
−2(a)(
a
1
)=25
=>a
2
+
a
2
1
=25+2
=27
Now,Putting the values,we get,
a
2
+
a
2
1
−3a+
a
3
= a
2
+
a
2
1
−3(a−
a
1
)
=27−3(5)
=27−15
=12
Answered by
0
( x + 1 /x ) = 5
( x + 1 / x )^2 = 25
= x^2 + 1 / x^2 + 2 * x * 1/x =25
= x ^2 + 1/x^2 + 2 = 25
= X^2 + 1 / x^2 = 25 - 2 = 23 Ans .
x^2+1/x^2
(x+1/x)^2 = x^2+1/x^2 +2
(5)^2 = x^2+1/x^2 + 2
25 = x^2+1/x^2 + 2
25-2 = x^2+1/x^2
23 = x^2+1/x^2
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