Math, asked by KushiKumari1123, 3 months ago

If x–1/x=5 ,find
x²+1/x²​–3x+3/x​

Answers

Answered by varadad25
8

Answer:

\displaystyle{{\boxed{\red{\sf\:x^2\:+\:\dfrac{1}{x^2}\:-\:3x\:+\:\dfrac{3}{x}\:=\:12}}}}

Step-by-step-explanation:

We have given that,

\displaystyle{\sf\:x\:-\:\dfrac{1}{x}\:=\:5}

We have to find the value of,

\displaystyle{\sf\:x^2\:+\:\dfrac{1}{x^2}\:-\:3x\:+\:\dfrac{3}{x}}

Now,

\displaystyle{\sf\:x^2\:+\:\dfrac{1}{x^2}\:-\:3x\:+\:\dfrac{3}{x}}

\displaystyle{\implies\sf\:\left(\:x\:-\:\dfrac{1}{x}\:\right)^2\:+\:2\:\times\:\cancel{x}\:\times\:\dfrac{1}{\cancel{x}}\:-\:3x\:+\:\dfrac{3}{x}\:\quad\:-\:-\:-\:[\:\because\:a^2\:+\:b^2\:=\:(\:a\:-\:b\:)^2\:+\:2ab\:]}

\displaystyle{\implies\sf\:\left(\:x\:-\:\dfrac{1}{x}\:\right)^2\:+\:2\:-\:3\:\left(\:x\:+\:\dfrac{1}{x}\:\right)}

\displaystyle{\implies\sf\:(\:5\:)^2\:+\:2\:-\:3\:\times\:5\:\quad\:-\:-\:-\:[\:Given\:]}

\displaystyle{\implies\sf\:25\:+\:2\:-\:3\:\times\:5}

\displaystyle{\implies\sf\:27\:-\:15}

\displaystyle{\implies\sf\:12}

\displaystyle{\therefore\:\underline{\boxed{\red{\sf\:x^2\:+\:\dfrac{1}{x^2}\:-\:3x\:+\:\dfrac{3}{x}\:=\:12}}}}

Answered by Anonymous
1

Answer:

yaa bro

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