if x+(1/x)=5, find x³-y³
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Given,
x+1/x = 5
To find: x^3-1/x^3 =?
from the identity, x^3-y^3=(x-y)(x^2+xy+y^2)
» x^3-1/x^3 = (x-1/x)(x^2+x.1/x +1/x^2)
or, x^3-1/x^3 = 5(x^2+1/x^2+1)
or,x^3-1/x^3 = 5([x+1/x]^2- 2x.1/x+1)
or,x^3-1/x^3 = 5(5^2 -2+1)
or,x^3-1/x^3 =5(25-1)
or,x^3-1/x^3 = 5(24)
or,x^3-1/x^3 = 120
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