Question

if x+1/x=5 then find the value of rootx +1/rootx ​

Answer 1

Answer:

Here is your answer...

Answer 2

Answer:

$(\sqrt{x} +\frac{1}{\sqrt{x} } )$ = ± √7

Step-by-step explanation:

We know,

$x + \frac{1}{x} = 5\\\\-----\\\\Now,\\\\(a+b)^2 = a^2 + 2ab+b^2\\\\=(\sqrt{x} +\frac{1}{\sqrt{x} } )^2 = (\sqrt{x})^2 + 2(\sqrt{x})(\frac{1}{\sqrt{x} }) + (\frac{1}{\sqrt{x} }) ^2\\\\(\sqrt{x} +\frac{1}{\sqrt{x} } )^2 = x + \frac{1}{x} + 2\\\\Given, x + \frac{1}{x} = 5\\\\So,\\\\(\sqrt{x} +\frac{1}{\sqrt{x} } )^2 = 5 +2\\\\(\sqrt{x} +\frac{1}{\sqrt{x} } )^2 = 7\\\\(\sqrt{x} +\frac{1}{\sqrt{x} } ) = [+-]\sqrt{7}$