Question

if x+1/x=5 then find value of 2x/3x2-5x+3

Answer 1

x+1/x=5
now
2x/(3x2-5x+3)
taking x common
we will get
2/(3x-5+3/x)
now
by rearranging
2/{(3(x+1/x)-5)}
putting the value
2/(15-5)=1/5

ans=1/5

Answer 2

Answer:

The value of $\frac{2x}{3x^2-5x+3}$ is, $\frac{1}{5}$.

Step by step explanation:

As per the statement:

If $x+\frac{1}{x}=5$                    [1]

Find the value of:

$\frac{2x}{3x^2-5x+3}$

Divide numerator and denominator by x, we have;

$\frac{\frac{2x}{x}}{\frac{3x^2-5x+3}{x}}$

⇒$\frac{2}{3x-5+\frac{3}{x}}$

⇒$\frac{2}{3(x+\frac{1}{x})-5}$            .....[2]

Substitute the value of [1] into [2] we have;

⇒$\frac{2}{3(5)-5}$

⇒ $\frac{2}{15-5}=\frac{2}{10}=\frac{1}{5}$

Therefore, the value of $\frac{2x}{3x^2-5x+3}$ is, $\frac{1}{5}$.