Question

If x+¹/x = 5 then find value of x² + 1/x² ? *
25
23
20
22​

Answer 1

Given

⇒ x + 1/x = 5

To find

⇒x² + 1/x²

Now take

⇒ x + 1/x = 5

Squaring on both side

⇒(x + 1/x)² = (5)²

using this identities

⇒(a + b)² = a² + 2ab + b²

we get

⇒x² + 1/x² + 2×x×1/x = 25

⇒x² + 1/x² + 2 = 25

⇒x² + 1/x² = 25 - 2

⇒x² + 1/x² = 23

Answer

⇒x² + 1/x² = 23

Answer 2

Step-by-step explanation:

Given

⇒ x + 1/x = 5

To find

⇒x² + 1/x²

Now take

⇒ x + 1/x = 5

Squaring on both side

⇒(x + 1/x)² = (5)²

using this identities

⇒(a + b)² = a² + 2ab + b²

we get

⇒x² + 1/x² + 2×x×1/x = 25

⇒x² + 1/x² + 2 = 25

⇒x² + 1/x² = 25 - 2

⇒x² + 1/x² = 23

Answer

⇒x² + 1/x² = 23

hope this helps you!!

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