if x+1/x=5 then x-1/x=?
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Answered by
3
Hi ,
x + 1/x = 5 ----( 1 )
( x - 1/x )² = ( x + 1/x )² - 4
= 5² - 4
= 25 - 4
= 21
x - 1/x = ±√21
I hope this helps you.
: )
x + 1/x = 5 ----( 1 )
( x - 1/x )² = ( x + 1/x )² - 4
= 5² - 4
= 25 - 4
= 21
x - 1/x = ±√21
I hope this helps you.
: )
pintu94:
how 4 come
Answered by
3
Method (1):
Given Equation is x + 1/x = 5.
On Squaring both sides, we get
(x + 1/x)^2 = (5)^2
x^2 + 1/x^2 + 2 * x * 1/x = 25
x^2 + 1/x^2 + 2 = 25
x^2 + 1/x^2 = 25 - 2
x^2 + 1/x^2 = 23 ----------- (1)
Now,
(x - 1/x)^2 = x^2 + 1/x^2 - 2
= 23 - 2
= 21.
Method (2):
We know that (a - b)^2 = (a + b)^2 - 4ab
Now,
(x - 1/x)^2 = (x + 1/x)^2 - 4 * x * 1/x
= (5)^2 - 4
= 25 - 4
= 21.
Hope this helps!
Given Equation is x + 1/x = 5.
On Squaring both sides, we get
(x + 1/x)^2 = (5)^2
x^2 + 1/x^2 + 2 * x * 1/x = 25
x^2 + 1/x^2 + 2 = 25
x^2 + 1/x^2 = 25 - 2
x^2 + 1/x^2 = 23 ----------- (1)
Now,
(x - 1/x)^2 = x^2 + 1/x^2 - 2
= 23 - 2
= 21.
Method (2):
We know that (a - b)^2 = (a + b)^2 - 4ab
Now,
(x - 1/x)^2 = (x + 1/x)^2 - 4 * x * 1/x
= (5)^2 - 4
= 25 - 4
= 21.
Hope this helps!
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