if x+1/x= 5 then x⁴+1/x²/x²-3x+1
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x+1/x=17………………..(1) given
(x^4+1/x^2)/(x^2-3x+1). =?
=(x^6+1)/x^2.x.(x-3+1/x).
=(x6+1)/x^3.(x+1/x-3).
=(x^3+1/x^3)/(x+1/x-3)
=[(x+1/x)^3–3(x+1/x)]/(x+1/x-3)
=[17^3–3.17]/(17–3)
=17(289–3)/14
=17×286/14. =17×143/7. =2431/7.
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