If X+1/X=√5Then
x-1/X=?
x2-1/X2=?
Answers
Step-by-step explanation:
1st squaring giving condition
by using 2nd formula of (a+b)^2=(a-b)^2+4ab
then we get the 1st result
for next we use the formula of a^2-b^2
and hence the result.....

Question:
If x + 1/x = √5, then find the value of :
- x - 1/x = ?
- x² - 1/x² = ?
Given:
- x + 1/x = √5......(I)
To find:
- x - 1/x = ?
- x² - 1/x² = ?
Solution:
- Since, x + 1/x = (√5)
(By squaring both sides)
=> ( x + 1/x )² = (√5)²
( By using ( a + b )² = a² + 2ab + b² )
=> x² + 2 × x × 1/x + 1/x² = 5
=> x² + 2 + 1/x² = 5
=> x² + 1/x² = 5 - 2
=> x² + 1/x² = 3
- Now, x² + 1/x² = 3
=> x² + 1/x² - 2 = 3 - 2
( By subtracting 2 from both sides)
=> x² + 1/x² - 2 × x × 1/x = 1
( There will be no change since x is going to be cancelled)
=> ( x - 1/x )² = 1
( By using ( a - b ) ² = a² - 2ab + b²)
=> ( x - 1/x ) = √1
( √1 is 1)
=> ( x - 1/x ) = 1.......(II)
Therefore, x - (1/x) = 1.
- Now, x² - 1/x² = ( x + 1/x ) ( x - 1/x )
( By using a² - b² = (a + b) (a - b))
=> x² - 1/x² = ( √5 ) (1)
( By putting the Values of ( x + 1/x ) = √5 from (I) and ( x - 1/x ) = 1 from (II))
=> x² - 1/x² = √5
Therefore, x² - 1/x² = √5.
Answer:
- x - 1/x = 1
- x² - 1/x² = √5