Math, asked by ssivaprasad758, 1 year ago

If x+1/x =6 ,find the values of : I) x2+1/x2. ii) x-1/x​

Answers

Answered by Jaizz
1

Answer:

i. 34 ii.32

Step-by-step explanation:

i. on squaring both sides

x2+1/x2 +2=36

x2+1/x2 =34

ii. on squaring both sides

= {x2+1/x2} -2

=34-2

=32

Answered by Anonymous
2

Answer:

{x}+{1/x} = 6

on squaring them

{x}^2+{1/x}^2 + 2 = 36

{x}^2+{1/x}^2 = 36 - 2

{x}^2+{1/x}^2 = 34

{x}-{1/x} = {x}^2+{1/x}^2 - 2

putting the value of

{x}^2+{1/x}^2

{x}-{1/x} = 34 + 2

{x}-{1/x} = 36

hope this help u

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