If x+1/x=6, find x^4+1/x^4
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Answered by
13
hello friend❤❤❤
here is your answer
x+1/x=6
(x+1/x)²=6²=36
x²+1/x²+2=36
x²+1/x²=36-2=34
(x²+1/x²)² =34²
x⁴+1/x⁴+2=1156
x⁴+1/x⁴=1156 -2=1154
hope it helped you☺☺☺
here is your answer
x+1/x=6
(x+1/x)²=6²=36
x²+1/x²+2=36
x²+1/x²=36-2=34
(x²+1/x²)² =34²
x⁴+1/x⁴+2=1156
x⁴+1/x⁴=1156 -2=1154
hope it helped you☺☺☺
BrainlyQueen01:
edit ur answer 34^2 = 1156 not 1136
Answered by
13
x + 1/x = 6
On squaring both sides, we get
x^2 + 1/x^2 + 2(x)(1/x) = 36
=> x^2 + 1/x^2 + 2 = 36
=> x^2 + 1/x^2 = 34
Again on squaring both sides, we get
x^4 + 1/x^4 + 2 = 1156
=> x^4 + 1/x^4 = 1154
On squaring both sides, we get
x^2 + 1/x^2 + 2(x)(1/x) = 36
=> x^2 + 1/x^2 + 2 = 36
=> x^2 + 1/x^2 = 34
Again on squaring both sides, we get
x^4 + 1/x^4 + 2 = 1156
=> x^4 + 1/x^4 = 1154
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