if x+1/x =66 find root x-1/root x
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hello users ...
Given that:
x+1/x =66
we have to find ;
(√x - 1/√x ) = ?
solution:-
we know that :
a² + b² = ( a-b)² + 2ab
Here,
we can write ...
x+1/x as (√x)² + (1/√x)²
=> (√x)² + (1/√x)² = (√x - 1/√x)² + 2 * √x * 1/√x
=> 66 = (√x - 1/√x)² + 2
=> (√x - 1/√x)² = 66 - 2 = 64
=> (√x - 1/√x)² = 8²
=> (√x - 1/√x) = 8 Answer
# hope it helps :)
Given that:
x+1/x =66
we have to find ;
(√x - 1/√x ) = ?
solution:-
we know that :
a² + b² = ( a-b)² + 2ab
Here,
we can write ...
x+1/x as (√x)² + (1/√x)²
=> (√x)² + (1/√x)² = (√x - 1/√x)² + 2 * √x * 1/√x
=> 66 = (√x - 1/√x)² + 2
=> (√x - 1/√x)² = 66 - 2 = 64
=> (√x - 1/√x)² = 8²
=> (√x - 1/√x) = 8 Answer
# hope it helps :)
avanish4:
but the answer is 6
no correct Answer is 8
see explaination
sorry ? is wrong
the question is x square +1/x square =66 find value of root x +1/root x
please give me answer
ok editing .....
no it is not possible !!
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