Question

if x+1/x=6find the values of. ii- x⁴+1/x⁴​

Answer 1

Answer:$Using:a^2 + b^2 = (a+b)^2 - 2ab-(A)\\x^{4} + 1/x^{4} = (x^{2})^2 + (1/x^{2})^2 \\= (x^2 + 1/x^2)^2 - 2.x^2.(1/x^2)-Using (A)\\= (x^2 + 1/x^2)^2 - 2(1)\\= (x^2 + 1/x^2)^2 - 2\\= ((x + 1/x)^2 - 2.x.(1/x))^2 - 2 -Using (A)\\= ((x + 1/x)^2 - 2(1))^2 - 2\\=((x + 1/x)^2 - 2)^2 - 2\\=(6^2 - 2)^2 - 2\\=(36 - 2)^2 - 2\\=(34)^2 - 2\\=1154$