Question

if x+1/x=7 find the value of :

x square 1/x square​

Answer 1

Answer:

x + 1x1x = 7 ⇒ (x + 1x1x)2 =(7)2 ⇒ (x2+ 1x21x2+ 2) = 49 ⇒ x2+ 1x21x2 = 47 Therefore, x2+ 1x21x2 = 47.

Step-by-step explanation:

Given: x + 1/x = 7 Squaring on both sides ⇒ (x  + 1/x )2 =(7)2 ⇒ x2 + ( 1/x)2 + 2(x)(1/x) = 49               [∵ (a+b)2= a2+b2 + 2ab] ⇒ x2 + 1/(x2) +  2 = 49 ⇒ x2 + 1/(x2)  = 49 - 2 ∴ x2 + 1/(x2)  = 47

Answer 2

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