If X +1/X =7;find the value of x³+1/x³
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Answered by
7
Given:
= > x + 1/x = 7
On cubing both sides, we get
= > (x + 1/x)^3 = (7)^3
= > x^3 +1/x^3 + 3 * x * 1/x(x + 1/x) = 343
= > x^3 + 1/x^3 + 3(7) = 343
= > x^3 + 1/x^3 + 21 = 343
= > x^3 + 1/x^3 = 322.
Therefore the value of x^3 + 1/x^3 = 322.
Hope this helps!
= > x + 1/x = 7
On cubing both sides, we get
= > (x + 1/x)^3 = (7)^3
= > x^3 +1/x^3 + 3 * x * 1/x(x + 1/x) = 343
= > x^3 + 1/x^3 + 3(7) = 343
= > x^3 + 1/x^3 + 21 = 343
= > x^3 + 1/x^3 = 322.
Therefore the value of x^3 + 1/x^3 = 322.
Hope this helps!
siddhartharao77:
:-)
Answered by
4
Hey !!!
x + 1/x = 7 ------1)
we know that
( a + b ) ² - 2ab = a² + b²
similarly in this term
(x + 1/x )²- 2x×1/x = x² + 1/x²
7² - 2 = x² + 1/x²
47 = x² + 1/x² ----------2)
•°• (a + b )³ = (a + b ) ( a² + b² - ab)
similarly
x³ + 1/x³ = ( x + 1/x) (x² + 1/x² - x×1/x)
x³ + 1/x² = 7 (47 - 1)
[putting value from 1st and 2nd equation ]
x³ + 1/x³ = 7× 46
x³ + 1/x³ = 322 Answer ✔
______________________
Hope it helps you !!!
@Rajukumar111
x + 1/x = 7 ------1)
we know that
( a + b ) ² - 2ab = a² + b²
similarly in this term
(x + 1/x )²- 2x×1/x = x² + 1/x²
7² - 2 = x² + 1/x²
47 = x² + 1/x² ----------2)
•°• (a + b )³ = (a + b ) ( a² + b² - ab)
similarly
x³ + 1/x³ = ( x + 1/x) (x² + 1/x² - x×1/x)
x³ + 1/x² = 7 (47 - 1)
[putting value from 1st and 2nd equation ]
x³ + 1/x³ = 7× 46
x³ + 1/x³ = 322 Answer ✔
______________________
Hope it helps you !!!
@Rajukumar111
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