if x+1/x=7,find value of x^3-1/x^3
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if; x+ 1/x=7
if; x+ 1/x=7then, (x+1/x)^2=7^2=49
if; x+ 1/x=7then, (x+1/x)^2=7^2=49or, (x+1/x)^2-4. x.1/x=49-4
if; x+ 1/x=7then, (x+1/x)^2=7^2=49or, (x+1/x)^2-4. x.1/x=49-4or, (x-1/x)^2=44
if; x+ 1/x=7then, (x+1/x)^2=7^2=49or, (x+1/x)^2-4. x.1/x=49-4or, (x-1/x)^2=44or, x-1/x=44^1/2
Now,,,,
x^3-1/x^3
=(x-1/x)(x^2-x. 1/x+1/x^2)
=(44^1/2){(x-1/x)^2+2x.1/x-x.1/x}
=(44^1/2) (44+1)
=45.44^1/2
tia1421:
Sry, the question is in minus
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