if x-1/x=7,find x31/x3
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Answered by
3
HEY!!
We know that ( a - b )3 = a3 + b3 - 3ab(a - b)
( x - 1)3 = x3 +1 - 3.x.1 (x - 1)
divide with x3
(x -1/x)3 =( x3 + 1)/x3 - 3x.7x/x3..........x-1=7x from problem
(7)3 = (x3 + 1)/x3 -21/x
343 + 21/x = x3 + 1/x3
We know that ( a - b )3 = a3 + b3 - 3ab(a - b)
( x - 1)3 = x3 +1 - 3.x.1 (x - 1)
divide with x3
(x -1/x)3 =( x3 + 1)/x3 - 3x.7x/x3..........x-1=7x from problem
(7)3 = (x3 + 1)/x3 -21/x
343 + 21/x = x3 + 1/x3
deepaksharma6:
kya h ye
Answered by
4
hy
here is your answer
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*************************
We know that ( a - b )³ = a³ + b³- 3ab(a - b)
( x - 1)³= x³+1 - 3.x.1 (x - 1)
divide with x³
(x -1/x)³=( x³+ 1)/x³ - 3x.7x/x³..........x-1=7x from problem
(7)³= (x³+ 1)/x³-21/x
343 + 21/x = x³ + 1/x³
=====================
here is your answer
=================
*************************
We know that ( a - b )³ = a³ + b³- 3ab(a - b)
( x - 1)³= x³+1 - 3.x.1 (x - 1)
divide with x³
(x -1/x)³=( x³+ 1)/x³ - 3x.7x/x³..........x-1=7x from problem
(7)³= (x³+ 1)/x³-21/x
343 + 21/x = x³ + 1/x³
=====================
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