Question

If x+1/x=7, then find the value of x^3 + 1/x^3​

Answer 1

$\bold{ANSWER}$

$\rm{322}$

$\mathbb{EXPLANATION}$

$\rm{x+\frac{1}{x}}$=$\rm{7}$

$\rm{\right(x+\frac{1}{x}\left)}$=$\rm{\right(7\left)}$

$\textit{Cubing\:On\:Both\:Sides\:We\:Have}$

$\rm{\right(x+\frac{1}{x}\left)^3}$=$\rm{\right(7\left)^3}$

$\rm{x^3\:+\frac{1}{x^3}+3\right(x+\frac{1}{x}\left)}=[tex]\rm{\right(7\left)^3}$

$\rm{x^3\:+\frac{1}{x^3}+3/right(7/left)}=[tex]\rm{\right(7\left)^3}$

$\rm{x^3\:+\frac{1}{x^3}}=[tex]\rm{\right(343-21\left)}$

$\therefore$ $\rm{x^3\:+\frac{1}{x^3}}$=

$\rm{\right(322\left)}$

Answer 2

Answer:

The above answer is right I saw that .

Step-by-step explanation:

Please mark as brilliant answer .