if x-1/x=7,then find the value of x4+1/x4
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Answered by
67
x - 1/x = 7
by squaring both side , we get
(x - 1/ x)^2 = (7)^2
x^2 + 1/x^2 - 2(x) (1/x) = 49
x^2 + 1/x^2 - 2 = 49
x^2 + 1/x^2 = 49 + 2
x^2 + 1/x^2 = 51
again ,by squaring both side , we get
(x^2 + 1/x^2)^2 = (51)^2
x^4 + 1/x^4 + 2(x^2) (1/x^2) = 2601
x^4 + 1/x^4 + 2= 2601
x^4 + 1/x^4 = 2601 - 2
x^4 + 1/x^4 = 2599
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|| Your Answer : 2599 ||
____________________________
by squaring both side , we get
(x - 1/ x)^2 = (7)^2
x^2 + 1/x^2 - 2(x) (1/x) = 49
x^2 + 1/x^2 - 2 = 49
x^2 + 1/x^2 = 49 + 2
x^2 + 1/x^2 = 51
again ,by squaring both side , we get
(x^2 + 1/x^2)^2 = (51)^2
x^4 + 1/x^4 + 2(x^2) (1/x^2) = 2601
x^4 + 1/x^4 + 2= 2601
x^4 + 1/x^4 = 2601 - 2
x^4 + 1/x^4 = 2599
____________________________
|| Your Answer : 2599 ||
____________________________
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