if x-1/x=7find the value of x^4+1/x^4
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Answered by
1
Hey !
Here is your answer !
_____________
➡[ x - 1 / x ]2 = x2 + 1 /x2 - 2
➡ [ 7 ]2 = x2 + 1 / x2 - 2
➡ 49 + 2 = x2 + 1 /x2
➡ 51 = x2 + 1 /x2
Now !
➡[x2 + 1 / x2 ]2 = x4 + 1 /x4 + 2
➡ [ 51 ]2 = x4 + 1 / x4 + 2
➡ 2601 - 2 = x4 + 1 / x4
➡2599 = x4 + 1 / x4
Hope it helps you !!!!
Here is your answer !
_____________
➡[ x - 1 / x ]2 = x2 + 1 /x2 - 2
➡ [ 7 ]2 = x2 + 1 / x2 - 2
➡ 49 + 2 = x2 + 1 /x2
➡ 51 = x2 + 1 /x2
Now !
➡[x2 + 1 / x2 ]2 = x4 + 1 /x4 + 2
➡ [ 51 ]2 = x4 + 1 / x4 + 2
➡ 2601 - 2 = x4 + 1 / x4
➡2599 = x4 + 1 / x4
Hope it helps you !!!!
Answered by
2
HELLO DEAR,
GIVEN THAT:-
x - 1/x = 7
∴ [ on squaring both side]
(x - 1/x)² = 7²
x² + 1/x² - 2*x*1/x = 49
(x² + 1/x²) = 49 + 2
(x² + 1/x²)² = 51²
∴[ on squaring both side]
x⁴ + 1/x⁴ + 2*x²*1/x² = 2601
(x⁴ + 1/x⁴) = 2601 - 2
(x⁴ + 1/x⁴) = 2599
I HOPE ITS HELP YOU DEAR, THANKS ♥️
GIVEN THAT:-
x - 1/x = 7
∴ [ on squaring both side]
(x - 1/x)² = 7²
x² + 1/x² - 2*x*1/x = 49
(x² + 1/x²) = 49 + 2
(x² + 1/x²)² = 51²
∴[ on squaring both side]
x⁴ + 1/x⁴ + 2*x²*1/x² = 2601
(x⁴ + 1/x⁴) = 2601 - 2
(x⁴ + 1/x⁴) = 2599
I HOPE ITS HELP YOU DEAR, THANKS ♥️
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