Math, asked by dortrix11, 1 year ago

if X+1/X=7THEN FIND XSQUARE+1/X SQUARE

dortrix11: hi

avinashkr232000: 47

dortrix11: ohh yes correct

avinashkr232000: your answer

dortrix11: thanks bro

shivi4211: 47

dortrix11: ok bro

shivi4211: my answer is 47

dortrix11: correct

avinashkr232000: X + 1 by X is equal to 7 both side square and find x square plus one upon x square is equal to 49-2 therefore its solution is 47

Answers

Answered by deadpool55

Hi mate

here is your answer

(x+1/x)²=49

x²+(1/x)²+2*x*(1/x)=49

x²+(1/x)²=49-2

=47

Hope it helps :)

dortrix11: thanks

deadpool55: your welcome bro

dortrix11: thanks

Answered by abdul9838

$<b> <body \: bgcolor = "skyblue">$

$\bf \blue{hey \: mate \: here \: is \: ans} \\ \\ \bf \blue{ \huge \: solution} \\ \\ \: \:\bf \blue{given \: that} \\ \\ \bf \blue{x + \frac{1}{x} = 7} \\ \\ \bf \blue{and \: we \: have \: to \: find \: the \: value \:of } \: \\ \bf \blue{ {x}^{2} + \frac{1}{ {x}^{2} } } \\ \\ \: \bf \blue{let \: start} \\ \\ \bf \blue{as \: given} \\ \\ \bf \blue{x + \frac{1}{x} = 7 } \\ \\ \bf \red{squaring \: on \: both \: sides} \\ \\ \bf \blue{(x + \frac{1}{x} )^{2} = {7}^{2} } \\ \\ \bf \blue{ {x}^{2} + \frac{1}{ {x}^{2} } + 2 \times x \times \frac{1}{x} = 49 } \\ \\ \bf \blue{ {x}^{2} + \frac{1}{ {x}^{2} } + 2 \times \cancel{x} \times \frac{1}{ \cancel{x}} = 49} \\ \\ \bf \blue{ {x}^{2} + \frac{1}{ {x}^{2} } = 49 - 2} \\ \\ \bf \blue{ {x}^{2} + \frac{1}{ {x}^{2} } = 47 \: \: answer} \\ \\ \\ \bf \orange{thanks \: for \: asking} \\ \\ \bf \purple{ \huge \: follow \: me}$

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if X+1/X=7THEN FIND XSQUARE+1/X SQUARE