if x+1/x=8 ,find the value of x^2+1/x^2
Answers
Answered by
11
hey your ans is here
______
given
x+1/x=8
to find
x2+1/x2
apply
(x+1/x)2=x2+1/x2+2
(8)2=x2+1/x2+2
64-2=x2+1/x2
62=x2+1/x2
_____
______
given
x+1/x=8
to find
x2+1/x2
apply
(x+1/x)2=x2+1/x2+2
(8)2=x2+1/x2+2
64-2=x2+1/x2
62=x2+1/x2
_____
Answered by
2
here
x^2+1/x^2
x+1/x=8
or,x+1=8x
7x=1
x=1/7
now
x^2+1/x^2
(x^2/x^2)+1/x^2
=1+1/x^2
=1+1/(1/7}^2
=1+49
=50
x^2+1/x^2
x+1/x=8
or,x+1=8x
7x=1
x=1/7
now
x^2+1/x^2
(x^2/x^2)+1/x^2
=1+1/x^2
=1+1/(1/7}^2
=1+49
=50
vyshnavivadla:
but i got answer 64
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