Question

If x+1/x = 8, find the value of x sq =1/x sq ​

Answer 1

Answer:

x + 1/x = 8

x² + 1/x² = ?

By squaring on both sides: [ using (a+b)² identity = a² + 2*a*b + b² ]

( x + 1/x )² = ( 8 )²

( x + 1/x )² = x² + 1/x² + 2*x*1/x = x² + 1/x² + 2

( 8 )² = 64

x² + 1/x² + 2 = 64

x² + 1/x² = 64 - 2

x² + 1/x² = 62