if X + 1 / x =8 find the value of x square + 1 / x square
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Answered by
1
(x+1/x)^2=x^2+1/x2+2
(8)^2 =x^2+1/x^2+2
64-2=x^2+1/x^2
62 =x^2+1/x^2
THANK YOU
(8)^2 =x^2+1/x^2+2
64-2=x^2+1/x^2
62 =x^2+1/x^2
THANK YOU
Answered by
121
❤
x+=8
On Squaring both sides:-
➾(x+ )²=(8)²
➾x²+ +2×x× =64
➾x²+ +2=64
➾x²+ =64-2
➾x²+ =62
Therefore the value of x²+ =62
Hope it's helpful ✔️
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